06 jul 2015, 15:49
06 jul 2015, 18:33
06 jul 2015, 19:42
pedrodaniel10 Escreveu:\(\log_{\sqrt{3}}27=\log_{\sqrt{3}}3^3=\log_{\sqrt{3}}\left (\sqrt{3}^2 \right )^3=\log_{\sqrt{3}}\sqrt{3}^6=6\)
06 jul 2015, 21:12
09 jul 2015, 00:04
ivandepaiva Escreveu:Como resolvo com Raiz na Base
\(Log_{\sqrt{3}}^{27}\)
Já sou grato pela força