veja a figura:
\(\frac{4}{2}=\frac{[4+(6-x)]}{x+2}
2=\frac{10-x}{x+2}
2x+4=10-x
x=2\)
\(8^2=4^2+a^2
a=4\sqrt{3}\)
\(4^2=2^2+b^2
b=2\sqrt{3}\)
\(\widehat{AD}=\frac{2}{3}.(2\pi.R)
\widehat{AD}=\frac{2}{3}.(2\pi.4)
\widehat{AD}=\frac{16\pi}{3}\)
\(\widehat{CB}=\frac{2}{3}.(2\pi.r)
\widehat{CB}=\frac{2}{3}.(2\pi.2)
\widehat{CB}=\frac{8\pi}{3}\)
Comprimento da corrente:
\(\widehat{AD}+\widehat{CB}+2a+2b=
\frac{16\pi}{3}+\frac{8\pi}{3}+2.(4\sqrt{3})+2.(2\sqrt{3})=\)
- Anexos
-
- circuferencia.jpg (70.76 KiB) Visualizado 1576 vezes